-0.2x^2+176x+21900=0

Solution for -0.2x^2+176x+21900=0 equation:

-0.2x^2+176x+21900=0

a = -0.2; b = 176; c = +21900;
Δ = b2-4ac
Δ = 1762-4·(-0.2)·21900
Δ = 48496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48496}=\sqrt{16*3031}=\sqrt{16}*\sqrt{3031}=4\sqrt{3031}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(176)-4\sqrt{3031}}{2*-0.2}=\frac{-176-4\sqrt{3031}}{-0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(176)+4\sqrt{3031}}{2*-0.2}=\frac{-176+4\sqrt{3031}}{-0.4}
$